\(\int \frac {(1-c^2 x^2)^{3/2}}{x (a+b \arcsin (c x))^2} \, dx\) [394]

   Optimal result
   Rubi [N/A]
   Mathematica [N/A]
   Maple [N/A] (verified)
   Fricas [N/A]
   Sympy [N/A]
   Maxima [N/A]
   Giac [F(-2)]
   Mupad [N/A]

Optimal result

Integrand size = 28, antiderivative size = 28 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=-\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {9 \cos \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a+b \arcsin (c x)}{b}\right )}{4 b^2}-\frac {3 \cos \left (\frac {3 a}{b}\right ) \operatorname {CosIntegral}\left (\frac {3 (a+b \arcsin (c x))}{b}\right )}{4 b^2}-\frac {9 \sin \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c x)}{b}\right )}{4 b^2}-\frac {3 \sin \left (\frac {3 a}{b}\right ) \text {Si}\left (\frac {3 (a+b \arcsin (c x))}{b}\right )}{4 b^2}-\frac {\text {Int}\left (\frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))},x\right )}{b c} \]

[Out]

-(-c^2*x^2+1)^2/b/c/x/(a+b*arcsin(c*x))-9/4*Ci((a+b*arcsin(c*x))/b)*cos(a/b)/b^2-3/4*Ci(3*(a+b*arcsin(c*x))/b)
*cos(3*a/b)/b^2-9/4*Si((a+b*arcsin(c*x))/b)*sin(a/b)/b^2-3/4*Si(3*(a+b*arcsin(c*x))/b)*sin(3*a/b)/b^2-Unintegr
able((-c^2*x^2+1)/x^2/(a+b*arcsin(c*x)),x)/b/c

Rubi [N/A]

Not integrable

Time = 0.24 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx \]

[In]

Int[(1 - c^2*x^2)^(3/2)/(x*(a + b*ArcSin[c*x])^2),x]

[Out]

-((1 - c^2*x^2)^2/(b*c*x*(a + b*ArcSin[c*x]))) - (9*Cos[a/b]*CosIntegral[(a + b*ArcSin[c*x])/b])/(4*b^2) - (3*
Cos[(3*a)/b]*CosIntegral[(3*(a + b*ArcSin[c*x]))/b])/(4*b^2) - (9*Sin[a/b]*SinIntegral[(a + b*ArcSin[c*x])/b])
/(4*b^2) - (3*Sin[(3*a)/b]*SinIntegral[(3*(a + b*ArcSin[c*x]))/b])/(4*b^2) - Defer[Int][(1 - c^2*x^2)/(x^2*(a
+ b*ArcSin[c*x])), x]/(b*c)

Rubi steps \begin{align*} \text {integral}& = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c}-\frac {(3 c) \int \frac {1-c^2 x^2}{a+b \arcsin (c x)} \, dx}{b} \\ & = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {3 \text {Subst}\left (\int \frac {\cos ^3\left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{b^2}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c} \\ & = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {3 \text {Subst}\left (\int \left (\frac {\cos \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{4 x}+\frac {3 \cos \left (\frac {a}{b}-\frac {x}{b}\right )}{4 x}\right ) \, dx,x,a+b \arcsin (c x)\right )}{b^2}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c} \\ & = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {3 \text {Subst}\left (\int \frac {\cos \left (\frac {3 a}{b}-\frac {3 x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2}-\frac {9 \text {Subst}\left (\int \frac {\cos \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c} \\ & = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c}-\frac {\left (9 \cos \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2}-\frac {\left (3 \cos \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2}-\frac {\left (9 \sin \left (\frac {a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2}-\frac {\left (3 \sin \left (\frac {3 a}{b}\right )\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {3 x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{4 b^2} \\ & = -\frac {\left (1-c^2 x^2\right )^2}{b c x (a+b \arcsin (c x))}-\frac {9 \cos \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a+b \arcsin (c x)}{b}\right )}{4 b^2}-\frac {3 \cos \left (\frac {3 a}{b}\right ) \operatorname {CosIntegral}\left (\frac {3 (a+b \arcsin (c x))}{b}\right )}{4 b^2}-\frac {9 \sin \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c x)}{b}\right )}{4 b^2}-\frac {3 \sin \left (\frac {3 a}{b}\right ) \text {Si}\left (\frac {3 (a+b \arcsin (c x))}{b}\right )}{4 b^2}-\frac {\int \frac {1-c^2 x^2}{x^2 (a+b \arcsin (c x))} \, dx}{b c} \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 8.85 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx \]

[In]

Integrate[(1 - c^2*x^2)^(3/2)/(x*(a + b*ArcSin[c*x])^2),x]

[Out]

Integrate[(1 - c^2*x^2)^(3/2)/(x*(a + b*ArcSin[c*x])^2), x]

Maple [N/A] (verified)

Not integrable

Time = 0.15 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93

\[\int \frac {\left (-c^{2} x^{2}+1\right )^{\frac {3}{2}}}{x \left (a +b \arcsin \left (c x \right )\right )^{2}}d x\]

[In]

int((-c^2*x^2+1)^(3/2)/x/(a+b*arcsin(c*x))^2,x)

[Out]

int((-c^2*x^2+1)^(3/2)/x/(a+b*arcsin(c*x))^2,x)

Fricas [N/A]

Not integrable

Time = 0.25 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.54 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int { \frac {{\left (-c^{2} x^{2} + 1\right )}^{\frac {3}{2}}}{{\left (b \arcsin \left (c x\right ) + a\right )}^{2} x} \,d x } \]

[In]

integrate((-c^2*x^2+1)^(3/2)/x/(a+b*arcsin(c*x))^2,x, algorithm="fricas")

[Out]

integral((-c^2*x^2 + 1)^(3/2)/(b^2*x*arcsin(c*x)^2 + 2*a*b*x*arcsin(c*x) + a^2*x), x)

Sympy [N/A]

Not integrable

Time = 3.02 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.96 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int \frac {\left (- \left (c x - 1\right ) \left (c x + 1\right )\right )^{\frac {3}{2}}}{x \left (a + b \operatorname {asin}{\left (c x \right )}\right )^{2}}\, dx \]

[In]

integrate((-c**2*x**2+1)**(3/2)/x/(a+b*asin(c*x))**2,x)

[Out]

Integral((-(c*x - 1)*(c*x + 1))**(3/2)/(x*(a + b*asin(c*x))**2), x)

Maxima [N/A]

Not integrable

Time = 0.92 (sec) , antiderivative size = 146, normalized size of antiderivative = 5.21 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int { \frac {{\left (-c^{2} x^{2} + 1\right )}^{\frac {3}{2}}}{{\left (b \arcsin \left (c x\right ) + a\right )}^{2} x} \,d x } \]

[In]

integrate((-c^2*x^2+1)^(3/2)/x/(a+b*arcsin(c*x))^2,x, algorithm="maxima")

[Out]

-(c^4*x^4 - 2*c^2*x^2 - (b^2*c*x*arctan2(c*x, sqrt(c*x + 1)*sqrt(-c*x + 1)) + a*b*c*x)*integrate((3*c^4*x^4 -
2*c^2*x^2 - 1)/(b^2*c*x^2*arctan2(c*x, sqrt(c*x + 1)*sqrt(-c*x + 1)) + a*b*c*x^2), x) + 1)/(b^2*c*x*arctan2(c*
x, sqrt(c*x + 1)*sqrt(-c*x + 1)) + a*b*c*x)

Giac [F(-2)]

Exception generated. \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((-c^2*x^2+1)^(3/2)/x/(a+b*arcsin(c*x))^2,x, algorithm="giac")

[Out]

Exception raised: TypeError >> an error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

Mupad [N/A]

Not integrable

Time = 0.15 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00 \[ \int \frac {\left (1-c^2 x^2\right )^{3/2}}{x (a+b \arcsin (c x))^2} \, dx=\int \frac {{\left (1-c^2\,x^2\right )}^{3/2}}{x\,{\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^2} \,d x \]

[In]

int((1 - c^2*x^2)^(3/2)/(x*(a + b*asin(c*x))^2),x)

[Out]

int((1 - c^2*x^2)^(3/2)/(x*(a + b*asin(c*x))^2), x)